Waec GCE 2018 Physics Practical Answers

For Any Exam Solution!! Always Visit www.naijaclass.com

Waec GCE 2018 Physics Practical Answers
  • WELCOME TO 9JACLASS.COM ONLINE ANSWERS

    ===============================
    WAEC GCE PHYSICS PRACTICAL


    (2a)
    Tabulate
    S/n | Ag/cm | 8C1/cm | tiata | U= Bc/Ac | cost Rita |

    Under S/n: 1, 2, 3, 4, 5

    Under Ag/cm: 7.10, 7.90, 8.10, 8.70, 9.35

    Under 8C1/cm: 2.10, 3.60, 4.25, 5.30, 6.40

    Under tita: 70, 46, 35, 25, 19

    Under U = Bc/Ac: 0.29, 0.45, 0.52, 0.60, 0.65

    Under cos tita: 0.34, 0.69, 0.80, 0.90, 0.94

    (2av)
    (I) I would avoid error due to parallax
    (II) I would ensure right Postion of the ruler while taking the reading

    (bii)
    H2 = 2cm, Do = 6cm
    H2 = 6cm
    H2 = 4.1cm
    M = Hi/Ho = 4.1/2
    = 2.05
    M = Di/Do = 2.05 = Di/6
    Di = 6 x 2.05 = 12.16
    = 12.3cm

    (2bii)
    Principal axis is an imaginary line passing through the center of the lens in which the principal force of the lens passes through.
    ===================


    (3a)
    R ohms
    R1 = 1ohms R3 = 3ohms
    R2 = 2ohms R4 = 4ohms
    R5 = 5ohms
    V1 = 1.90v
    V2 = 2.15v
    V3 = 2.3v
    V4 = 2.40v
    V5 = 2.5v

    In a tabular form
    Under S/N
    1, 2, 3, 4, 5

    Under R(ohms )
    1.00, 2.00, 3.00, 4.00, 5.00

    Under V(v)
    1.90, 2.15, 2.30, 2.40, 2.50

    Under R^-1(ohms^-1)
    1.000, 5.000, 0.333, 0.250, 0.200

    Under V^-1(V^-1)
    0.5263, 0.465, 0.4347, 0.4167, 0.400

    Under R^-1/V^-1
    1.900, 1.07, 0.768, 0.5999, 0.500

    (3avi)
    (i) Ensure tight connections.
    (ii) Avoid error due to parallax when reading the voltmeter

    (3b)
    (i) Length of wire
    (ii) Nature of wire

    (3bii)
    Total resistance,
    R = 3 + (3×3)/(3+3)
    R = 4.5 ohms
    Current, I = V/R
    I = 6/4.5
    I = 1.33 A


    ====================

    1aix )
    i ) I avoided parallax error in reading clock / weight balance
    ii) I ensue repeated readings are taken to avoid random error
    ========================================
    3x)
    i ) I would ensure that the terminal are well tightened to avoid partial contact
    ii) I would obey the connection of positive to positive to negative when connecting to circuit.

    (1a)
    Pls Tabulate:
    xi(cm)|yi(cm)|zi(cm)|W1(Nx10^-2)|W2(Nx10^-2)|u=(w1-w2)(Nx10^-2)|v=(w1-w3)(Nx10-2)
    =>1.80|1.50|1.70|3.6|3.00|3.40|0.60|0.20
    =>3.80|3.00|3.00|7.6|6.00|6.00|1.60|1.60
    =>5.50|4.40|5.00|11.10|8.00|10.00|2.20|1.00
    =>7.30|5.90|6.60|14.60|11.80|13.00|2.80|1.40
    =>9.20|7.30|8.30|18.40|14.60|16.60|3.80|1.80
    =>11.10|8.30|10.00|22.20|16.60|20.00|5.60|2.20


    (1b)
    Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. Specific gravity usually means relative density with respect to water.

    (1bii)
    Given volume of solid immersed
    Vsi =1/2*30cm³
    =15cm³
    Density of liquid (water)ew= 1g/cm³
    Acceleration due to gravity, g = 10m/s²
    Upthrust, U= eVsi g
    U= 1000*(15*10^-6)*10
    U=15*10-²
    U=0.15N
    Weight of solid =mg
    =EsVs g
    given: Es=2.4g/cm³ (2400kg/m³)
    Vs=30cm (30*10^-6 m³)
    g=10m/s²
    Weight, w=30*10^-6*2400*10
    =72*10-²
    =0.72N
    Reading on spring balance =W-U
    =0.72-0.15
    =0.57N
    ==============================


    NO 2



    =========GOOD BYE-------------===========



    Share With Facebook Friends



  • Exam!! Click Here To REFRESH CLICK HERE NOW!


    Comments Section

    Reply By:
  • |>>>> U ar d best

  • Reply By:
  • |>>>> U ar d best

  • Reply By: abba sani
  • |>>>> its really awesome the way you guys are doing

  • Reply By:
  • |>>>>

  • Reply By:
  • |>>>> U ar d best

  • [1][2][Next][Last]
    SCAM ALERT!
    Do Not Call Any Number Or Visit Any Website You See On This Comment Section.